x^2-654x+16328=0

Solution for x^2-654x+16328=0 equation:

x^2-654x+16328=0

a = 1; b = -654; c = +16328;
Δ = b2-4ac
Δ = -6542-4·1·16328
Δ = 362404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{362404}=602$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-654)-602}{2*1}=\frac{52}{2}
=26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-654)+602}{2*1}=\frac{1256}{2}
=628
$